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(√2+√6) (√3-√2)=![]()
(√2+√6) (√3-√2)=
( √2 + √6 ) ( √3 - √2 )
= ( √2 + √6 ) × ( √3 - √2 )
= √16 - 2 + √18 - 2√3
= √6-2 + √3²×2 - 2√3
= √6 - 2 + √3² × √2 - 2√3
= √6 - 2 + 3√2 - 2√3
Zz!
Penyelesaian ;
[tex]( \sqrt{2} + \sqrt{6} )( \sqrt{3} - \sqrt{2} ) \\ \\ = \sqrt{16} - 2 + \sqrt{18} - 2 \sqrt{3} \\ \\ = \sqrt{6} - 2 + \sqrt{3 \times 3} \times \sqrt{2} - 2\sqrt{3} \\ \\ \green{= \sqrt{6} - 2 + 3 \sqrt{2} - 2\sqrt{3} }[/tex]
